7x/3=x^2/6

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Solution for 7x/3=x^2/6 equation: 


x in (-oo:+oo)

(7*x)/3 = (x^2)/6 // - (x^2)/6

(7*x)/3-((x^2)/6) = 0

7/3*x-1/6*x^2 = 0

DELTA = (7/3)^2-(-1/6*0*4)

DELTA = 49/9

DELTA > 0

x = ((49/9)^(1/2)-7/3)/(-1/6*2) or x = (-(49/9)^(1/2)-7/3)/(-1/6*2)

x = 0 or x = 14

x in { 0, 14 }

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